Identifier
Values
[] => 0
[1] => 0
[2] => 1
[1,1] => 0
[3] => 1
[2,1] => 1
[1,1,1] => 0
[4] => 1
[3,1] => 1
[2,2] => 1
[2,1,1] => 1
[1,1,1,1] => 0
[5] => 1
[4,1] => 1
[3,2] => 1
[3,1,1] => 1
[2,2,1] => 1
[2,1,1,1] => 1
[1,1,1,1,1] => 0
[6] => 1
[5,1] => 1
[4,2] => 2
[4,1,1] => 1
[3,3] => 1
[3,2,1] => 2
[3,1,1,1] => 1
[2,2,2] => 1
[2,2,1,1] => 1
[2,1,1,1,1] => 1
[1,1,1,1,1,1] => 0
[7] => 1
[6,1] => 1
[5,2] => 2
[5,1,1] => 1
[4,3] => 1
[4,2,1] => 2
[4,1,1,1] => 1
[3,3,1] => 1
[3,2,2] => 1
[3,2,1,1] => 2
[3,1,1,1,1] => 1
[2,2,2,1] => 1
[2,2,1,1,1] => 1
[2,1,1,1,1,1] => 1
[1,1,1,1,1,1,1] => 0
[8] => 1
[7,1] => 1
[6,2] => 2
[6,1,1] => 1
[5,3] => 2
[5,2,1] => 2
[5,1,1,1] => 1
[4,4] => 1
[4,3,1] => 1
[4,2,2] => 2
[4,2,1,1] => 2
[4,1,1,1,1] => 1
[3,3,2] => 1
[3,3,1,1] => 1
[3,2,2,1] => 2
[3,2,1,1,1] => 2
[3,1,1,1,1,1] => 1
[2,2,2,2] => 1
[2,2,2,1,1] => 1
[2,2,1,1,1,1] => 1
[2,1,1,1,1,1,1] => 1
[1,1,1,1,1,1,1,1] => 0
[9] => 1
[8,1] => 1
[7,2] => 2
[7,1,1] => 1
[6,3] => 2
[6,2,1] => 2
[6,1,1,1] => 1
[5,4] => 1
[5,3,1] => 2
[5,2,2] => 2
[5,2,1,1] => 2
[5,1,1,1,1] => 1
[4,4,1] => 1
[4,3,2] => 2
[4,3,1,1] => 1
[4,2,2,1] => 2
[4,2,1,1,1] => 2
[4,1,1,1,1,1] => 1
[3,3,3] => 1
[3,3,2,1] => 2
[3,3,1,1,1] => 1
[3,2,2,2] => 1
[3,2,2,1,1] => 2
[3,2,1,1,1,1] => 2
[3,1,1,1,1,1,1] => 1
[2,2,2,2,1] => 1
[2,2,2,1,1,1] => 1
[2,2,1,1,1,1,1] => 1
[2,1,1,1,1,1,1,1] => 1
[1,1,1,1,1,1,1,1,1] => 0
[10] => 1
[9,1] => 1
[8,2] => 2
[8,1,1] => 1
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Description
The number of lower covers of a partition in dominance order.
According to [1], Corollary 2.4, the maximum number of elements one element (apparently for $n\neq 2$) can cover is
$$ \frac{1}{2}(\sqrt{1+8n}-3) $$
and an element which covers this number of elements is given by $(c+i,c,c-1,\dots,3,2,1)$, where $1\leq i\leq c+2$.
According to [1], Corollary 2.4, the maximum number of elements one element (apparently for $n\neq 2$) can cover is
$$ \frac{1}{2}(\sqrt{1+8n}-3) $$
and an element which covers this number of elements is given by $(c+i,c,c-1,\dots,3,2,1)$, where $1\leq i\leq c+2$.
References
[1] Brylawski, T. The lattice of integer partitions MathSciNet:0325405
Code
@cached_function
def P(k):
return posets.IntegerPartitionsDominanceOrder(k)
def statistic(pi):
Q = P(pi.size())
return len(Q.lower_covers(Q(pi)))
Created
May 09, 2016 at 09:22 by Martin Rubey
Updated
Oct 29, 2017 at 21:36 by Martin Rubey
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