Identifier
-
Mp00199:
Dyck paths
—prime Dyck path⟶
Dyck paths
Mp00093: Dyck paths —to binary word⟶ Binary words
Mp00096: Binary words —Foata bijection⟶ Binary words
St001423: Binary words ⟶ ℤ
Values
[1,0] => [1,1,0,0] => 1100 => 0110 => 0
[1,0,1,0] => [1,1,0,1,0,0] => 110100 => 011100 => 1
[1,1,0,0] => [1,1,1,0,0,0] => 111000 => 001110 => 1
[1,0,1,0,1,0] => [1,1,0,1,0,1,0,0] => 11010100 => 01111000 => 2
[1,0,1,1,0,0] => [1,1,0,1,1,0,0,0] => 11011000 => 00111010 => 1
[1,1,0,0,1,0] => [1,1,1,0,0,1,0,0] => 11100100 => 01011100 => 1
[1,1,0,1,0,0] => [1,1,1,0,1,0,0,0] => 11101000 => 00111100 => 1
[1,1,1,0,0,0] => [1,1,1,1,0,0,0,0] => 11110000 => 00011110 => 2
[] => [1,0] => 10 => 10 => 0
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Description
The number of distinct cubes in a binary word.
A factor of a word is a sequence of consecutive letters. This statistic records the number of distinct non-empty words u such that uuu is a factor of the word.
A factor of a word is a sequence of consecutive letters. This statistic records the number of distinct non-empty words u such that uuu is a factor of the word.
Map
to binary word
Description
Return the Dyck word as binary word.
Map
Foata bijection
Description
The Foata bijection ϕ is a bijection on the set of words of given content (by a slight generalization of Section 2 in [1]).
Given a word w1w2...wn, compute the image inductively by starting with ϕ(w1)=w1. At the i-th step, if ϕ(w1w2...wi)=v1v2...vi, define ϕ(w1w2...wiwi+1) by placing wi+1 on the end of the word v1v2...vi and breaking the word up into blocks as follows.
For instance, to compute ϕ(4154223), the sequence of words is
Given a word w1w2...wn, compute the image inductively by starting with ϕ(w1)=w1. At the i-th step, if ϕ(w1w2...wi)=v1v2...vi, define ϕ(w1w2...wiwi+1) by placing wi+1 on the end of the word v1v2...vi and breaking the word up into blocks as follows.
- If wi+1≥vi, place a vertical line to the right of each vk for which wi+1≥vk.
- If wi+1<vi, place a vertical line to the right of each vk for which wi+1<vk.
For instance, to compute ϕ(4154223), the sequence of words is
- 4,
- |4|1 -- > 41,
- |4|1|5 -- > 415,
- |415|4 -- > 5414,
- |5|4|14|2 -- > 54412,
- |5441|2|2 -- > 154422,
- |1|5442|2|3 -- > 1254423.
Map
prime Dyck path
Description
Return the Dyck path obtained by adding an initial up and a final down step.
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