Identifier
- St001565: Permutations ⟶ ℤ
Values
[1] => 0
[1,2] => 0
[2,1] => 0
[1,2,3] => 1
[1,3,2] => 0
[2,1,3] => 0
[2,3,1] => 0
[3,1,2] => 0
[3,2,1] => 1
[1,2,3,4] => 2
[1,2,4,3] => 1
[1,3,2,4] => 0
[1,3,4,2] => 0
[1,4,2,3] => 1
[1,4,3,2] => 1
[2,1,3,4] => 1
[2,1,4,3] => 0
[2,3,1,4] => 1
[2,3,4,1] => 1
[2,4,1,3] => 0
[2,4,3,1] => 0
[3,1,2,4] => 0
[3,1,4,2] => 0
[3,2,1,4] => 1
[3,2,4,1] => 1
[3,4,1,2] => 0
[3,4,2,1] => 1
[4,1,2,3] => 1
[4,1,3,2] => 1
[4,2,1,3] => 0
[4,2,3,1] => 0
[4,3,1,2] => 1
[4,3,2,1] => 2
[1,2,3,4,5] => 4
[1,2,3,5,4] => 3
[1,2,4,3,5] => 2
[1,2,4,5,3] => 1
[1,2,5,3,4] => 2
[1,2,5,4,3] => 2
[1,3,2,4,5] => 2
[1,3,2,5,4] => 1
[1,3,4,2,5] => 2
[1,3,4,5,2] => 2
[1,3,5,2,4] => 1
[1,3,5,4,2] => 1
[1,4,2,3,5] => 2
[1,4,2,5,3] => 1
[1,4,3,2,5] => 2
[1,4,3,5,2] => 2
[1,4,5,2,3] => 1
[1,4,5,3,2] => 1
[1,5,2,3,4] => 2
[1,5,2,4,3] => 2
[1,5,3,2,4] => 0
[1,5,3,4,2] => 0
[1,5,4,2,3] => 2
[1,5,4,3,2] => 2
[2,1,3,4,5] => 3
[2,1,3,5,4] => 2
[2,1,4,3,5] => 1
[2,1,4,5,3] => 0
[2,1,5,3,4] => 1
[2,1,5,4,3] => 1
[2,3,1,4,5] => 2
[2,3,1,5,4] => 1
[2,3,4,1,5] => 2
[2,3,4,5,1] => 2
[2,3,5,1,4] => 1
[2,3,5,4,1] => 1
[2,4,1,3,5] => 1
[2,4,1,5,3] => 0
[2,4,3,1,5] => 0
[2,4,3,5,1] => 0
[2,4,5,1,3] => 0
[2,4,5,3,1] => 1
[2,5,1,3,4] => 1
[2,5,1,4,3] => 1
[2,5,3,1,4] => 2
[2,5,3,4,1] => 2
[2,5,4,1,3] => 1
[2,5,4,3,1] => 2
[3,1,2,4,5] => 1
[3,1,2,5,4] => 0
[3,1,4,2,5] => 1
[3,1,4,5,2] => 1
[3,1,5,2,4] => 0
[3,1,5,4,2] => 0
[3,2,1,4,5] => 2
[3,2,1,5,4] => 1
[3,2,4,1,5] => 2
[3,2,4,5,1] => 2
[3,2,5,1,4] => 1
[3,2,5,4,1] => 1
[3,4,1,2,5] => 1
[3,4,1,5,2] => 1
[3,4,2,1,5] => 2
[3,4,2,5,1] => 2
[3,4,5,1,2] => 1
[3,4,5,2,1] => 2
[3,5,1,2,4] => 0
[3,5,1,4,2] => 0
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Description
The number of arithmetic progressions of length 2 in a permutation.
For a permutation of length $n$, this is the number of indices $1 \leq i < j < k \leq n$ such that $\pi(k) - \pi(j) = \pi(j) - \pi(i)$.
For a permutation of length $n$, this is the number of indices $1 \leq i < j < k \leq n$ such that $\pi(k) - \pi(j) = \pi(j) - \pi(i)$.
Code
def statistic(pi):
n = len(pi)
return sum(1 for k in range(n) for j in range(k) for i in range(j) if pi[k] - pi[j] == pi[j] - pi[i])
Created
Jul 15, 2020 at 08:24 by Christian Stump
Updated
Jul 15, 2020 at 08:24 by Christian Stump
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