Identifier
Values
[] => 1
[1] => 1
[2] => 2
[1,1] => 2
[3] => 1
[2,1] => 4
[1,1,1] => 4
[4] => 2
[3,1] => 1
[2,2] => 10
[2,1,1] => 10
[1,1,1,1] => 10
[5] => 1
[4,1] => 2
[3,2] => 2
[3,1,1] => 2
[2,2,1] => 26
[2,1,1,1] => 26
[1,1,1,1,1] => 26
[6] => 4
[5,1] => 1
[4,2] => 4
[4,1,1] => 4
[3,3] => 4
[3,2,1] => 4
[3,1,1,1] => 4
[2,2,2] => 76
[2,2,1,1] => 76
[2,1,1,1,1] => 76
[1,1,1,1,1,1] => 76
[7] => 1
[6,1] => 4
[5,2] => 2
[5,1,1] => 2
[4,3] => 2
[4,2,1] => 8
[4,1,1,1] => 8
[3,3,1] => 4
[3,2,2] => 10
[3,2,1,1] => 10
[3,1,1,1,1] => 10
[2,2,2,1] => 232
[2,2,1,1,1] => 232
[2,1,1,1,1,1] => 232
[1,1,1,1,1,1,1] => 232
[8] => 4
[7,1] => 1
[6,2] => 8
[6,1,1] => 8
[5,3] => 1
[5,2,1] => 4
[5,1,1,1] => 4
[4,4] => 12
[4,3,1] => 2
[4,2,2] => 20
[4,2,1,1] => 20
[4,1,1,1,1] => 20
[3,3,2] => 8
[3,3,1,1] => 8
[3,2,2,1] => 26
[3,2,1,1,1] => 26
[3,1,1,1,1,1] => 26
[2,2,2,2] => 764
[2,2,2,1,1] => 764
[2,2,1,1,1,1] => 764
[2,1,1,1,1,1,1] => 764
[1,1,1,1,1,1,1,1] => 764
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Description
The number of permutations such that conjugation with a permutation of given cycle type yields the inverse permutation.
Let $\alpha$ be any permutation of cycle type $\lambda$. This statistic is the number of permutations $\pi$ such that
$$ \alpha\pi\alpha^{-1} = \pi^{-1}.$$
Let $\alpha$ be any permutation of cycle type $\lambda$. This statistic is the number of permutations $\pi$ such that
$$ \alpha\pi\alpha^{-1} = \pi^{-1}.$$
References
[1] Homolya, S., Szigeti, Jenő Solving equations in the symmetric group arXiv:2104.03593
Code
def statistic(la):
total = 0
cycles = []
for p in la:
cycles.append(tuple(range(total+1, total+p+1)))
total += p
a = Permutation(cycles)
return sum(1 for pi in Permutations(len(a)) if pi*a*pi == a)
Created
Apr 09, 2021 at 11:05 by Martin Rubey
Updated
Apr 09, 2021 at 11:05 by Martin Rubey
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